Two tuning forks are producing sounds of wavelength

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The discussion focuses on calculating the number of beats heard when two tuning forks produce sounds with wavelengths of 36.0 cm and 33.8 cm. The speed of sound is given as 345 m/s, allowing for the calculation of frequencies for each fork: 958 Hz for the first and 1020.7 Hz for the second. The difference in frequencies results in 63 beats per second. This calculation confirms the expected auditory phenomenon when two slightly different frequencies are played simultaneously. The final conclusion is that 63 beats per second will be heard.
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Two tuning forks are producing sounds of wavelength 36.0 cm and 33.8 cm simultaneously. How many beats do you hear each second?



I know that the # of beats/sec heard is equal to the difference of frequency 2 and 1. Frequency = 1/T = v/lambda.



Don't feel that I have enough information
 
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Start by figuring out the frequencies of those sounds. Hint: You'll need the speed of sound.
 
Okay, so the speed of sound v=345 m/s
F1 = 345m/s / .36m
=958 Hz

F2 = 345m/s / .338m
=1020.7 Hz

so then beats/second = 1020.7-958??
=63 beats/second
 
Sounds about right.
 

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