Two unequal charges repel, suspended from same point.

AI Thread Summary
Two identical spheres with unequal charges repel each other when suspended from the same point, creating angles θ and θ' from the vertical. The problem involves determining the relationship between these angles when one charge is three times the other (q1 = 3q2) and finding the distance between the spheres in terms of their charges and other physical constants. Initial attempts incorrectly assumed the forces were perpendicular to the vertical, leading to an inaccurate ratio of the sine of the angles. Clarification suggests that the forces should be considered horizontal due to the small angle approximation. Understanding the correct alignment of forces is crucial to solving the problem accurately.
Darkwolf312
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1. Two small, identical spheres of mass m each are attached to thin light threads of length L each and hung from the same point. When charges q1 and q2 are placed on upon the spheres(with both charges having the same sign), the two spheres repel each other and, upon reaching equilibrium, hang at angles \theta and \theta' from the vertical.
a) If q1= 3q2, what is \theta' in terms of \theta? (Hint: Consider Newton's Third Law)
b) Draw a free-body diagram for either sphere, and hence find the distance x between the spheres in terms of q1, q2, L, m, and any necessary physical constants. Assume that \theta is small such that \theta \approx Sin\theta \approxTan\theta

Homework Equations


F= kq1q2/d2

The Attempt at a Solution


In my first attempt at the problem, I assumed the forces caused by the charges were perpendicular to the vertical and thus got the answer Sin\theta/Sin\theta' = 1. I think this answer is incorrect, but I got it by equating the two forces caused by the charges, and hence equating the x-component of the two tension forces.

I guess the correct way to do it would be to take the electrostatic forces as being in line with the distance, but I can't seem to figure out the angle between the force and the horizontal. I am also unsure as to whether I should use the statement given in part b as how small \theta is. Any help would be greatly appreciated.
 
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Welcome to PF!

Hi Darkwolf312! Welcome to PF! :smile:

(hav a theta: θ :wink:)
Darkwolf312 said:
Assume that \theta is small such that \theta \approx Sin\theta \approxTan\theta

In my first attempt at the problem, I assumed the forces caused by the charges were perpendicular to the vertical and thus got the answer Sin\theta/Sin\theta' = 1. I think this answer is incorrect, but I got it by equating the two forces caused by the charges, and hence equating the x-component of the two tension forces.

I guess the correct way to do it would be to take the electrostatic forces as being in line with the distance, but I can't seem to figure out the angle between the force and the horizontal.

Yes, you're correct, the force is in line with the distance :smile:

but you should assume that the charges are at the same level, so that the forces are horizontal …

that's what the question is trying to get at :rolleyes: when it talks about θ being small! :wink:
 
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