U.S. Spam %: P=13+45*ln*x (2003) - Right or Wrong?

[poohbear1986]

P=13+45*ln*x represents the percentage of inbound e-mail in the U.S. that is considered spam, where x is the number of years after 2000. say you use 2003, i keep figurin out this out and i get 12.18 and 5.045, i like to have someone tell me if I am right or wrong

 

[symbolipoint]

P=13+45*ln*x represents the percentage of inbound e-mail in the U.S. that is considered spam, where x is the number of years after 2000. say you use 2003, i keep figurin out this out and i get 12.18 and 5.045, i like to have someone tell me if I am right or wrong

Do you mean \[<br /> P = 13 + 45\ln (x)<br /> \]<br /> ?

The natural log of 3 is about 1.0986, or close to 1.10,
so in your example, P = 62.5

 

[CRGreathouse]

Do you mean \[<br /> P = 13 + 45\ln (x)<br /> \]<br /> ?

What a model... it suggests that all email will be spam as of November of last year.

 

[Feldoh]

What a model... it suggests that all email will be spam as of November of last year.

Pretty much matches my inbox