Uncovering Projectile Motion Properties

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The discussion focuses on analyzing the projectile motion of an object launched with an unknown initial velocity that lands on a hill after 19.8 seconds, covering 2710 meters horizontally and rising 463 meters vertically. To find the vertical component of the initial velocity, the kinematic equation is applied, considering the time of flight and gravitational acceleration. The horizontal component is determined similarly, using the horizontal distance traveled. The maximum height is calculated by determining the time when the vertical velocity reaches zero. Finally, the speed and angle of the projectile upon impact with the hill are derived from its velocity components at the time of landing.
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A projectile, fired with unknown initial velocity, lands 19.8 s later on the side of a hill, 2710 m away horizontally and 463 m vertically above its starting point. (Ignore any effects due to air resistance.)

(a) What is the vertical component of its initial velocity?
(b) What is the horizontal component of its initial velocity?
(c) What was its maximum height above its launch point?
(d) As it hit the hill, what speed did it have and what angle did its velocity make with the vertical?




Known 2D kinematics equations



3. How would you do this, I have no idea.
 
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It's just like the baseball problem you did.
Start with the y component.
y = y_0 + v_y t + \frac{1}{2} a t^2

Assuming y_0 = 0
y(t=19.8 s) = 463 m = v_y (19.8s) + \frac{1}{2} (-9.8 m/s) (19.8s)^2

Part b is similar.

Part c. Find the time when v_y = 0.

Part d. From the components of velocity at t = 19.8s, what is the speed? What is the direction?
 
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