Understand Newton's law of universal gravitation

AI Thread Summary
The discussion revolves around calculating the gravitational force acting on Earth due to the Sun using Newton's law of universal gravitation. The initial calculation resulted in an incorrect exponent due to a calculator error, prompting clarification on the correct approach. Participants emphasized the importance of accurately computing the gravitational constant multiplied by Earth's mass divided by the radius squared, leading to the correct value of approximately 9.81 m/s². Additionally, there were requests for more context on the problem to aid understanding. The conversation highlights the significance of precision in physics calculations.
aligass2004
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Homework Statement


http://i241.photobucket.com/albums/ff4/alg5045/1012540B.jpg

Consider the Earth following its nearly circular orbit (dashed curve) about the sun. The Earth has mass 5.98 *10^24 kg and the sun has mass 1.99 *10^30 kg. They are separated, center to center, by r=93 million miles=150 million km. What is the size of the gravitational force acting on the Earth due to the sun?

Homework Equations



F = G(mE)(mS)/r^2

The Attempt at a Solution



Pretty much I just plugged and chugged to try to get the answer, which of course of was incorrect.

F = (6.67*10^-11)(5.98*10^24)(1.99*10^30)/ (1.5*10^11)^2 = 3.53*10^66
 
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Hi aligass2004,

aligass2004 said:

Homework Statement


http://i241.photobucket.com/albums/ff4/alg5045/1012540B.jpg

Consider the Earth following its nearly circular orbit (dashed curve) about the sun. The Earth has mass 5.98 *10^24 kg and the sun has mass 1.99 *10^30 kg. They are separated, center to center, by r=93 million miles=150 million km. What is the size of the gravitational force acting on the Earth due to the sun?

Homework Equations



F = G(mE)(mS)/r^2

The Attempt at a Solution



Pretty much I just plugged and chugged to try to get the answer, which of course of was incorrect.

F = (6.67*10^-11)(5.98*10^24)(1.99*10^30)/ (1.5*10^11)^2 = 3.53*10^66

I think you have a calculator error here. If you multiply these numbers together, you don't get an exponent of 66.
 
aligass2004 said:
That was the problem. Thank you!

http://i241.photobucket.com/albums/ff4/alg5045/1012540D.jpg

Now it asks for the value of the composite constant (GmE/r^2), to be multiplied by the mass of the object mO in the following equation?

http://i241.photobucket.com/albums/ff4/alg5045/render.gif

What is the statement of the problem?

I'm assuming re is not the radius of the earth, or you could just calculate that quantity from what you already have. Are the forces cancelling on that object, or is something else happening?
 
Last edited:
r is the radius of the earth. I still just don't understand what it's asking for.
 
If you can, please post the entire problem (all parts, even those that you may not have gotten too yet) exactly as its written, and maybe I or someone else can help you interpret it.

If all you need is the gravitational constant G times the mass of the Earth divided by the radius of the Earth squared, you can find those quantitites easily (they are usually inside the covers of the first-year physics textbooks).
 
"Now it asks for the value of the composite constant (GmE/r^2), to be multiplied by the mass of the object mO in the following equation?"


The solution to the composite constant is simply 9.8 m/s^2.

Convert the radius of 6.38*10^3 km to meters... which is 6,380,000 m
(GmE/r^2)= (6.67*10^-11)(5.98*10^24)/(6,380,000)^2

Calculate this and you will get 9.81 m/s^2
 
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