Understand Physics Equations: Distance & Velocity

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The discussion centers around understanding the distance and velocity formulas in the context of a specific problem involving a bike's acceleration. It highlights that these formulas vary based on the physical situation presented. The bike accelerates from 0 to 5.5 m/s in 4.5 seconds, then travels at that constant speed for an additional 3 seconds. The distance covered during acceleration can be calculated using the formula d = (1/2)at^2, where 'a' is acceleration and 't' is time. The conversation emphasizes the need for context to accurately apply these equations.
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well i need couple equations described to me. first the distance formula, and velocity. can you guys show me the steps and describe it for me THANKS :smile:
 
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There is no single distance formula and no single velocity formula. They depend on the particular physical situation which you have neglected to share with us.
 
sorry A bike first accelerates from 0.0m's to 5.5m/s in 4,5s, then continures at this constant speed for another 3.0s what is the total distance traveled by the bike?
 
Doesn't your textbook show them and weren't they covered in class??

Starting from rest the distance traversed with constant acceleration is a t^2 /2 and the speed acquired is at. I'll let you think about the second part! :-)
 

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