Understanding BJT Emitter Resistance: Explained by Horowitz & Hill

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Discussion Overview

The discussion revolves around the concept of intrinsic emitter resistance (re) in bipolar junction transistors (BJTs), particularly in the context of emitter follower circuits as described in the book by Horowitz & Hill. Participants explore the placement and implications of this resistance in circuit analysis.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses confusion regarding the placement of intrinsic emitter resistance (re) in emitter follower circuits, noting that Horowitz & Hill place it from the emitter to ground.
  • Another participant questions the assumption that the resistors shown in the circuit images are indeed the intrinsic emitter resistance, pointing out that they are not labeled as such.
  • A different participant clarifies that r'e (the AC impedance of the base-emitter junction) is typically considered in conjunction with the output impedance of an emitter follower, which involves both the actual resistor from emitter to ground and other factors.
  • There is a discussion about the expression for output impedance, with one participant suggesting a correction regarding the relationship between beta and the base circuit impedance.
  • A later post emphasizes the importance of having a pull-down resistor on the emitter output to prevent floating potential when the external load is disconnected.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct interpretation of the intrinsic emitter resistance placement and its implications in the circuit. Multiple competing views and corrections are presented without resolution.

Contextual Notes

There is uncertainty regarding the definitions and labeling of resistances in the circuit diagrams, as well as the mathematical expressions related to output impedance, which remain unresolved.

garibaldi
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Hey everyone,

Im currently reading Horowitz & Hill and am a little confused on the topic of the intrinsic emitter resistance (re). I understand that this resistance is essentially the dynamic resistance of the base-emitter diode.

I assumed that when analyzing a circuit this resistance should always be placed in series with the emitter. However H&H seem to place this resistance from the emitter to ground in the emitter followers they demonstrate.

In the case of the emitter follower circuit this makes sense because the low re means that the circuit will have a low output resistance as expected. I just don't understand why they placed it to ground.

The circuits in question are attached.
 

Attachments

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What makes you think that the resistors from emitter to ground shown in the images are re, the intrinsic emitter resistance? They aren't labeled re.
 
I think you mean r'e or pronounced 'R prime E' or 'R E prime'. Summarized, R'e is the AC impedance of the base emitter junction. Normally the output imedance of an emitter follower is Re (actual resistor from emitter to ground) in parallel with [(beta*the base circuit impedance) + r'e].
 
You say:

"Normally the output imedance of an emitter follower is Re (actual resistor from emitter to ground) in parallel with [(beta*the base circuit impedance) + r'e]."

Shouldn't the "(beta*the base circuit impedance)" expression be something more like "(the base circuit impedance/beta)"? Actually, I think the "beta" should be "beta+1".
 
The Electrician said:
You say:

"Normally the output imedance of an emitter follower is Re (actual resistor from emitter to ground) in parallel with [(beta*the base circuit impedance) + r'e]."

Shouldn't the "(beta*the base circuit impedance)" expression be something more like "(the base circuit impedance/beta)"? Actually, I think the "beta" should be "beta+1".

Yes, my bad.
 
It is usually a good idea to have a pull-down resistor on the emitter output to keep the output potential from floating up to the base potential when the external load is not connected. It is absolutely necessary if the external load does not have a dc path to ground.
 

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