Understanding Centrifuge Acceleration on Mercury

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The discussion centers on calculating the acceleration at a point halfway out in a centrifuge, given that the outer end produces an acceleration of 3.70 g. Participants clarify that when the radius is halved, the linear velocity also decreases, which affects acceleration. The formula a = V^2/R is emphasized, revealing that halving the radius results in halving the acceleration, not doubling it. The relationship between angular velocity and linear velocity is also discussed, highlighting that acceleration is dependent on the square of the velocity divided by the radius. Overall, understanding the dynamics of circular motion is crucial for solving the problem accurately.
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Homework Statement



A laboratory centrifuge on Earth makes n rpm (rev/min) and produces an acceleration of 3.70 g at its outer end.

a.) What is the acceleration g's at a point halfway out to the end?

Homework Equations



a = (V^2)/R

The Attempt at a Solution



I really don't know what to do. I thought that if you divide the radius by 2, the acceleration would double, according to the equation. That doesn't seem to be the case since the answer 7.40 is incorrect. Any help would be greatly appreciated.
 
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cdlegendary said:

Homework Statement



A laboratory centrifuge on Earth makes n rpm (rev/min) and produces an acceleration of 3.70 g at its outer end.

a.) What is the acceleration g's at a point halfway out to the end?

Homework Equations



a = (V^2)/R

The Attempt at a Solution



I really don't know what to do. I thought that if you divide the radius by 2, the acceleration would double, according to the equation. That doesn't seem to be the case since the answer 7.40 is incorrect. Any help would be greatly appreciated.

Do you remember how to calculate linear velocity from angular velocity? If radius changes, but angular velocity is constant, does linear velocity change?
 
Uhhh no I don't know how to calculate the linear velocity. I'm guessing the linear velocity changes if the radius changes eh? Only formula I'm familiar with is the a = V^2/R, and the other variation.
 
cdlegendary said:
Uhhh no I don't know how to calculate the linear velocity. I'm guessing the linear velocity changes if the radius changes eh? Only formula I'm familiar with is the a = V^2/R, and the other variation.

w * r = v

because w = radians / second

What is archlength? radians * radius (for example, 2pi radians (360 degrees) * r = circumference , the entire arch length)
so we get archlength/ second, which is a velocity along the rim of a circle.

The fact that v changes with r makes sense too: if you were going 1 revolution(360 degrees) a second, and you were right next to the pivot, you'd travel less distance per second. If you were 70 thousand miles away from the pivot going around every second, you'd be traveling VERY fast.
 
xcvxcvvc said:
w * r = v

because w = radians / second

What is archlength? radians * radius (for example, 2pi radians (360 degrees) * r = circumference , the entire arch length)
so we get archlength/ second, which is a velocity along the rim of a circle.

The fact that v changes with r makes sense too: if you were going 1 revolution(360 degrees) a second, and you were right next to the pivot, you'd travel less distance per second. If you were 70 thousand miles away from the pivot going around every second, you'd be traveling VERY fast.

Ah okay, thanks. So that would mean since the radius is halved, the linear velocity would be halved as well? If that's the case, then I would assume that the acceleration is quadrupled since both velocity and radius are being halved?
 
cdlegendary said:
Ah okay, thanks. So that would mean since the radius is halved, the linear velocity would be halved as well? If that's the case, then I would assume that the acceleration is quadrupled since both velocity and radius are being halved?

If a = V^2/ r = w^2 r^2 / r = W^2 r
then changing r by a factor of 1/2 would half the acceleration.
 
xcvxcvvc said:
If a = V^2/ r = w^2 r^2 / r = W^2 r
then changing r by a factor of 1/2 would half the acceleration.

Haha wow I got confused there for a sec. I see how it works now, thanks a lot !
 
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