Understanding Complex Plane and Finding Arguments: A Scientist's Perspective

SUSUSUSUSUSUSUSU

Homework Statement


The picture below.

Homework Equations


cos2x=1-2sinx
sin2x= 2sinxcosx

The Attempt at a Solution



I got the modulus by using the Pythagoras theorem which is 2sin theta

But I faced difficulty to find the argument. I have no idea why i end up with tan a (alpha) = cot theta which is not the right answer. on the answer booklet, it's written that it is tan a = -cot theta. I do not understand that why it comes to negative...? I just did tan a = sin2x/(1-cos2x) = cot x. Is it just because it is -isin2x?I think after that i can solve it.

Thank you.
 

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SUSUSUSUSUSUSUSU said:

Homework Statement


The picture below.

Homework Equations


cos2x=1-2sinx
sin2x= 2sinxcosx

The Attempt at a Solution



I got the modulus by using the Pythagoras theorem which is 2sin theta

But I faced difficulty to find the argument. I have no idea why i end up with tan a (alpha) = cot theta which is not the right answer.
on the answer booklet, it's written that it is tan a = -cot theta. I do not understand that why it comes to negative...? I just did tan a = sin2x/(1-cos2x) = cot x. Is it just because it is -isin2x?
Yes. The imaginary component is ##-\sin(2\theta)##.
SUSUSUSUSUSUSUSU said:
I think after that i can solve it.

Thank you.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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