Understanding Dimensional Analysis and Deriving M = L^3 T^-2 for Mass

  • Thread starter Thread starter HotMintea
  • Start date Start date
  • Tags Tags
    Derive
AI Thread Summary
Dimensional analysis of mass using Newton's equations suggests that mass can be expressed as [length]^3 [time]^-2. However, there is skepticism regarding this claim, with some participants asserting that mass cannot be represented in this way. The discussion highlights the need for a valid equation for force that aligns with the dimensional analysis. Concerns are raised about the credibility of the source that proposed this relationship. Overall, the conversation emphasizes the importance of rigorous analysis in deriving physical quantities.
HotMintea
Messages
42
Reaction score
0

Homework Statement



"Maxwell showed that we can easily do a dimensional analysis on mass, using only Newton’s equations. Mass is [length]^3 [time]^-2 ." (http://milesmathis.com/coul.html)

I would like to know how to do the dimensional analysis and derive M = L^3 T^-2.

2. The attempt at a solution

Since the right side of F\ = \frac{dp}{dt} has M^1, I think I need another equation for force that has M^n on the right side, where n ≠ 1.
 
Physics news on Phys.org
Mass is definitely not [length]^3 [time]^-2. That link is a crackpot website.
 
ideasrule said:
Mass is definitely not [length]^3 [time]^-2. That link is a crackpot website.

That may be why the author did not cite the source!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top