Understanding Dynode Multiplication in Scintillation Detectors

  • Thread starter Thread starter m-i-t-o
  • Start date Start date
  • Tags Tags
    Tube
m-i-t-o
Messages
8
Reaction score
0
Hi all,my question is on dynodes. For ex: in scintillation detector we ususally say that a visible photon when incident on photocathode,undergoes photoelectric effect.But what the process occurring on dynodes when this photoelectron incident on it.
Electrons are multiplying successively as moving from one dynode to other.What you called such a process,this is not photo electric effect! as instead of photon electron is incidenting on material.
Please help
 
Physics news on Phys.org
The photoelectric effect is just creating the first electrons, then these electrons are accelerated towards metal plates and will blast out electrons from it, and these will be accelerated to another metal piece etc.

The electrons are IONIZING the atoms in the metal, ionization due to collisions you might call it. (c.f collision ionization in hot and dense astrophysical gases etc.)
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Back
Top