Understanding Energy Changes in Motion

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When a body accelerates or decelerates, there is a change in kinetic energy (K.E.) due to the change in velocity. The relationship between kinetic energy and potential energy (P.E.) depends on the context; in frictionless motion, the total energy remains constant, but K.E. does not equal P.E. when an object moves up an incline. Satellites in orbit can lose energy due to atmospheric drag if they are within the Earth's atmosphere, as demonstrated by the case of SKYLAB. The extent of atmospheric influence on satellites depends on their orbital altitude, with higher altitudes experiencing less drag. Understanding these concepts is crucial for analyzing energy changes in motion.
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Hi. I'd like some help with the following please:

1. When a body accelerates or decelerates, is there definitely a change in K.E.?
2. When an object moves up an incline, is K.E. = P.E.?
3. Do satellites orbitting in space lose energy due to air resistance?

I know they're very simple but I haven't found a textbook that answers these particular questions. I can attempt them but I could be very wrong somewhere.
I guess my answers would be:

1. Yes, because the velocity is changing.
2. Yes, if the object is projected up the plane. I am not sure what happens if a constant force is applied.
3. My teacher says yes. I am unwilling to believe there is air resistance in space but I wonder if satellites do lose energy, maybe due to something else.

Any help is welcome.

Thanks
 
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1. Correct. (EDIT: as Doc Al had pointed out below, only in st line motion.)
2. In frictionless motion, KE+PE is constant.
3. They do. Look up what happened to SKYLAB.
 
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Amy T said:
3. My teacher says yes. I am unwilling to believe there is air resistance in space but I wonder if satellites do lose energy, maybe due to something else.

It depends on the orbital altitude of the satellite. If it is orbiting in Earth's atmosphere, then air resistance will exist.

Like Shooting star mentioned, SKYLAB had this problem (due to solar activity increasing the drag on it). The orbital altitude was 286 miles per one article I read. And since the outer layer of Earth's atmosphere (exosphere) is like 400-800 miles, it encountered air resistance.

CS
 
Amy T said:
Hi. I'd like some help with the following please:

1. When a body accelerates or decelerates, is there definitely a change in K.E.?
I guess my answers would be:

1. Yes, because the velocity is changing.
Careful here: Velocity is a vector and can change in direction as well as in magnitude.

Imagine something traveling a circular path at constant speed. Is it accelerating? Is its KE changing?
 
oo and what if its velocity doubles but it loses a quarter of its mass in the process?(like something a rocket might do)
 
Doc Al, you did it again. I considered only rectilinear motion, just because of the simplicity of the questions. Hi Amy T, take note of this.

Amy T said:
3. My teacher says yes. I am unwilling to believe there is air resistance in space but I wonder if satellites do lose energy, maybe due to something else.

Why don't you find out how much the "atmosphere" extends, and how far up some of the satellites are placed in orbit?

blochwave said:
oo and what if its velocity doubles but it loses a quarter of its mass in the process?(like something a rocket might do)

I think the OP is talking about a single object here.
 
And probably just linear motion but we just wanted to make you look bad!

Incidentally I was asked in a job interview how often I think the ISS's orbit needs to be corrected because of the very little atmospheric drag. I was wrong then, and I forget the answer, but not often!
 
blochwave said:
And probably just linear motion but we just wanted to make you look bad!

You have to come up with something LOTS better than that.
 
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Shooting star said:
1. Correct. (EDIT: as Doc Al had pointed out below, only in st line motion.)
2. In frictionless motion, KE+PE is constant.
3. They do. Look up what happened to SKYLAB.

2. But the problem asked if KE= PE.
 
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HallsofIvy said:
2. But the problem asked if KE= PE.

It's simple to deduce from what I've written that the answer in no. I have given more information.

(What's troubling you, HallsofIvy?)
 
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