Understanding formula F=GmM/r^2 confusion help

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The discussion revolves around calculating the gravitational force of attraction between Mars and a 2900 kg satellite in orbit at a distance of 1.6 times Mars' radius. The relevant formula used is F=GmM/r^2, where G is the gravitational constant, m is the mass of Mars, M is the mass of the satellite, and r is the distance from the center of Mars to the satellite. There is confusion regarding the measurement of the satellite's height, specifically whether it should be measured from Mars' surface or its center. The participants reference a previous thread for additional context on similar problems. Clarifying the height measurement is crucial for accurate calculations.
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Homework Statement



Scientists want to place a 2900.0 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 1.6 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:



mmars = 6.4191 x 10^23 kg
rmars = 3.397 x 10^6 m
G = 6.67428 x 10^-11 N-m2/kg2

1) What is the force of attraction between Mars and the satellite?




Homework Equations



F=GmM/r^2

The Attempt at a Solution




((6.67428e-11)*(6.491e+23)*(2900))/(1.6*3.397e+6)^2
 
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