Understanding Functor Categories in Graded Abelian Groups

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Homework Statement


Let \mathbb N be the discrete category of natural numbers. Describe the functor category \mathrm{Ab}^{\mathbb N} (commonly known as the category of graded abelian groups).

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The Attempt at a Solution


Since \mathbb N is discrete, a functor \mathbb N\xrightarrow A\mathrm{Ab} is simply a sequence (A_n) = A_0,A_1,\dots of abelian groups; an arrow (A_n)\xrightarrow{\sigma} (B_n) is given by arrows A_0\xrightarrow{\sigma_0}B_0, A_1\xrightarrow{\sigma_1}B_1,\dots.

This looks right, but seems too simple to me. I don't know very much about grading, but I thought there had to be some way of "going up the A's" (like \otimes\colon V^{\otimes i}\times V^{\otimes j}\to V^{\otimes i+j} in the case of the tensor algebra)
 
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For a graded ring you need to have an i thing times a j thing be an i+j thing. Since this problem is just with abelian groups, there is no such condition.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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