Understanding geometry problem in relativity

AI Thread Summary
The discussion revolves around a geometry problem in relativity, specifically focusing on the derivation of equation 2.4 from figure 2.3 in a provided document. The user expresses confusion about the disappearance of the term Δt² from the right side of the equation and questions the notation where cΔt² equals Δt², noting that it assumes geometric units without clarification. There is an attempt to understand the relationship between the equations, but the user remains uncertain about the second equality in equation 2.4. The conversation highlights the complexities of understanding geometric interpretations in the context of relativity. Overall, the thread emphasizes the need for clearer explanations in the context of relativity problems.
Vrbic
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Homework Statement


It is not ordinary problem, it is connected to it. I don't understand a figure and how is described. The problem is here http://www.pmaweb.caltech.edu/Courses/ph136/yr2011/1102.2.K.pdf How did equation 2.4 from figure 2.3 arise? Why disappear ##\Delta t^2## from the right?
Another question is: In the text above eq.2.4 is written ##c\Delta t^2=\Delta t^2##?? Ok, if it says work in geometric units where ##c=1## ok, but it isn't mentioned.

Homework Equations


eq 2.4 ##\Delta s^2=-\Delta t^2+\Delta x^2+\Delta y^2=-(2h-\Delta y^2)+\Delta y^2##

The Attempt at a Solution


An attempt occurred in my mind, when I thought about it half an hour :-)

Thank you all.
 
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jedishrfu said:
So you figured it out?
No, second equality in 2.4 is out of me. ##-\Delta t^2+\Delta x^2+\Delta y^2=-(2h-\Delta y)^2 + \Delta y^2##
 
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