- #1
KylieB
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Homework Statement
An 18g ice cube at -4.0ºC is placed into 75g of water at 10 ºC in an
insulated container.
a. What is the final temperature of the system?
b. How much of the ice melts?
I have a sheet full of these & ice to water to steam I really need somone to explain how to find the results so I can get my brain around these
Homework Equations
Q=MCΔT
C ice =2.09j/g°c
Cwater = 4.186j/g°c
M=Mass in g
T = temp in Degrees C
Q=ML
M=Mass in g
Lice =334j/g
The Attempt at a Solution
So here's what i think is right so far
Raise the temp of ice to 0
18 x 2.09 x 4 = 150 joules
Remove this energy from the water
150.48=75 x 4.186 x(10-Tf)is this part right?
150.48= 3139.5-313.95(Tf)
I am not sure how to get to the resultant temp of the water propery before I consider a phase change in the ice but I have a feeling there won't be enough heat energy in the water to melt all of the ice.
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