Understanding High Pass Filter: Plate Behavior and Phase Shift

AI Thread Summary
In a high pass filter circuit with a capacitor in series with a resistor, at frequencies much higher than the corner frequency, the output voltage (Vout) on the opposite plate of the capacitor closely follows the input voltage with minimal phase shift. When a high-frequency sine wave is applied, the rapid changes in voltage at the input are mirrored at the output, preventing significant voltage differences across the capacitor. This behavior ensures that the current remains within the limits supported by the resistor. Therefore, at high frequencies, the system effectively transmits the input signal without phase distortion. Understanding this relationship is crucial for analyzing high pass filter performance.
d.arbitman
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I'm having a hard time visualizing what happens on the plates of the capacitor in series with a resistor in a high pass filter circuit. When the input to the capacitor is high, assuming a sine wave (say +5V) what happens on the opposite plate of the capacitor (Vout)? Should the output follow the input (ie. is there no phase shift)?
 
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d.arbitman
At frequencies much higher than the corner frequency, the output side of the capacitor will follow the input side with no phase difference (in the limit). Imagine a very rapid change of voltage on the input side of the capacitor. If the output did not follow this rapid change then we would have created a rapid change in voltage *across* the capacitor (dV/dt) which, in turn, would imply larger current (i = C dV/dt) than can be supported by the resistor.
 
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