Understanding Homogeneous Differential Equation Simplification

[snowJT]

This is a basic simplification, but I'm going to post this here because it becomes homogeneous, and I know v = \frac{y}{x} but I don't see this simplification, I don't understand how it gets from this...

\frac{dy}{dx} = \frac{y-x}{y+x}

To THIS:

= \frac{v-1}{v+1} (I'm just only showing the RHS here)

If someone wouldn't mind explaining it, that would be great because I'm lost, unless this is a special rule.

 

[cristo]

Well, let y=vx, then sub into the RHS and you get \frac{vx-x}{vx+x}=\frac{x(v-1)}{x(v+1)}=\frac{v-1}{v+1}

 

[snowJT]

oh wow, that's incredible, I get it, thanks cristo

 

[cristo]

oh wow, that's incredible, I get it, thanks cristo

You're welcome!