Understanding Kepler's Second Law of Motion

AI Thread Summary
Kepler's second law states that the line connecting a planet to the sun sweeps out equal areas in equal times. A user seeks clarification on whether the areas swept out during equal time intervals are equal, using specific points in the planet's orbit as examples. Responses confirm that the interpretation is correct, noting that while the areas are not perfect triangles due to the curvature of the orbit, the principle holds true. The discussion emphasizes understanding the relationship between time and area in planetary motion. This reinforces the concept of equal area being swept out in equal time intervals as a fundamental aspect of Kepler's second law.
logearav
Messages
329
Reaction score
0

Homework Statement



Kepler's second law states that " The line joining the planet and the sun sweeps out equal areas in equal times"

Homework Equations



Please refer the attachment i have given

The Attempt at a Solution


Does this mean the area of the triangle on the left is equal to the area of the triangle on the right? I interpret in this way, i.e., when planet takes 5 hours ( say) to move from A to B it sweeps out the area given in red lines and when it moves from the position C, after 5 hrs, it reaches the position D, so according to Kepler's law the area swept out when planet moves from C to D is same as A To D. Am i right, revered members? correct me if i am wrong.
 

Attachments

  • KEPLER.gif
    KEPLER.gif
    1.2 KB · Views: 597
Physics news on Phys.org
You are interpreting it correctly. Remember that the areas in red and green are not exactly triangles, since the orbit is curved. Aside from this, your statements are correct.
 
Thanks for the reply phyzguy
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top