Understanding Line Integrals: Scalar vs Vector Fields

cshum00
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Well i know that the line integral is
36b2dc0ff136923eb88a33c1f36d7ca8.png
given a scalar function f. equation1

But the line integral is also
cf0ea5b21fdf24a36e4b98844ccd673b.png
given a vector field F. equation2

So, given scalar function f and taking the gradient vector of it in order to turn it into a vector field F. Why is equation1 not equal to equation2?
 
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It's not clear to me what you are asking. If F(r)= \nabla f then it is certainly true that \int_C \nabla F\cdot dr= \int_a^b \nabla F(r)\cdot r'(t)dt. But I don't know what you mean by "equation1 equal to equation2".
 
Given \nabla f = F(r)
\int_a^b f(r(t)) |r'(t)|dt \neq \int_a^b F(r(t)) \cdot r'(t)dt
Why?
 
cshum00 said:
Given \nabla f = F(r)
\int_a^b f(r(t)) |r'(t)|dt \neq \int_a^b F(r(t)) \cdot r'(t)dt
Why?
Why should \int_a^b f(r(t)) |r'(t)|dt \neq \int_a^b \nabla f(r(t)) \cdot r'(t)dt?
 
Well, let's try some example:

Let f(x,y) = xy
F=\nabla f(x,y)=<y,x>

Curve C => y=x, 0<x<1
Parametrize r(t)=<t,t>, 0<t<1
r'(t)=<1,1>
|r'(t)|=\sqrt2

f(r(t))=t^2
F(r(t))=<t,t>

If \int_a^b f(r(t))|r'(t)|dt = \int_a^b F(r(t)) \cdot r'(t)dt
\int_0^1 t^2 \sqrt2dt = \int_0^1 <t,t> \cdot <1,1>dt
(\sqrt2/3) t^3 |_0^1 = \int_0^1 2t dt
\sqrt2/3 = t^2 |_0^1
\sqrt2/3 \neq 1
 
The only reason i have been asking this:
\int_a^b f(r(t)) |r'(t)|dt \neq \int_a^b \nabla f(r(t)) \cdot r'(t)dt
is because the formula given on the book say that they should be equal. However, as i try many examples; i never get the same answer. Here is some general proof i have been trying but never got far.

Let f(x,y)=f(x,y)
F = \nabla f(x,y)=<f_x, f_y>

Let Parametrization of Curve C:
r(t) = <g(t), h(t)>
r'(t) = <g'(t), h'(t)>
|r'(t)| = [g'(t)^2 + h'^2(t)]^\frac{1}{2}

\int_a^b f(r(t)) |r'(t)|dt = \int_a^b \nabla f(r(t)) \cdot r'(t)dt
\int_a^b f(g(t), h(t))[g'(t)^2 + h'(t)^2]^\frac{1}{2}dt = \int_a^b <f(_x, f_y> \cdot <g'(t), h'(t)>dt
\int_a^b f(g(t), h(t))[g'(t)^2 + h'(t)^2]^\frac{1}{2}dt = \int_a^b g'(t)f_x(g(t), h(t))+ h'(t)f_y(g(t), h(t))dtSince limits and variable of integration are the same then
f(g(t), h(t))[g'(t)^2 + h'(t)^2]^\frac{1}{2} = g'(t)f_x(g(t), h(t)) + h'(t)f_y(g(t), h(t))
But since i don't have any idea of what is going on inside those partial derivatives, i don't have a clue how to proceed.

Edit: In addition, the right hand side kind of looks like the product rule of a derivative.
 
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