Understanding Logarithm Functions: f(x) = log(100x)

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SUMMARY

The discussion centers on the logarithmic function f(x) = log(100x) with base ten. It is established that this function can be expressed as f(x) = log(x) + 2, indicating a vertical translation of the graph up by two units. Additionally, the function represents a horizontal compression of the graph of log(x) by a factor of 1/100. Both interpretations describe the same function but highlight different transformations: one vertical and one horizontal.

PREREQUISITES
  • Understanding of logarithmic functions and their properties
  • Familiarity with graph transformations (translations and compressions)
  • Basic knowledge of function notation and manipulation
  • Experience with base ten logarithms
NEXT STEPS
  • Study the properties of logarithmic functions in detail
  • Learn about graph transformations, specifically vertical and horizontal shifts
  • Explore the concept of function equivalence and different representations
  • Practice graphing logarithmic functions and their transformations
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Students learning mathematics, educators teaching logarithmic functions, and anyone interested in understanding function transformations and their graphical representations.

nesan
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We're learning logarithms in school. I asked my teacher this question but she couldn't explain it very well.

For a function such as f(x) = log(100x), base ten of course.

When graphed I could say the graph is "compressed by a factor of 1 / 100"

or

Rewriting f(x) = log(100x) into f(x) = logx + log100 = logx + 2

Now it's f(x) = logx + 2

which is a vertical translation up two units. Why is it both? O.o

What do they have in relation? ]

Please and thank you, just want to understand this. >_<
 
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nesan said:
We're learning logarithms in school. I asked my teacher this question but she couldn't explain it very well.

For a function such as f(x) = log(100x), base ten of course.

When graphed I could say the graph is "compressed by a factor of 1 / 100"

or

Rewriting f(x) = log(100x) into f(x) = logx + log100 = logx + 2

Now it's f(x) = logx + 2

which is a vertical translation up two units. Why is it both? O.o

What do they have in relation? ]

Please and thank you, just want to understand this. >_<


It is not both: it is the same as the graph of log x but translated two units.

DonAntonio
 
DonAntonio said:
It is not both: it is the same as the graph of log x but translated two units.

DonAntonio

Why is it the same?
 
I think you just showed why it's the same. Think of as the number 5. 4 + 1 = 5, 3 + 2 = 5, there can be two ways to write the same number, and in much the same way we can write some functions in multiple ways.
 
If you take any point (x, y) on the graph of y = log(x), you'll see that there is a point (x/100, y) on the graph of f(x) = log(100x), so one way of looking at the graph of f is that it represents a compression toward the y-axis of the graph of y = log(x) by a factor of 100.

On the other hand, the same point (x, y) on the graph of y = log(x) corresponds to the point (x, y + 2) on the graph of y = log(x) + 2, so this version of the function represents a translation up by 2 units.

Although log(100x) ##\equiv## log(x) + 2, we're looking at two different transformations, one in the horizontal direction, and one in the vertical direction. All we are doing is looking at one thing in two different ways.
 

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