Understanding Matrices Sums and Products

cosmos42
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Homework Statement


Suppose that AB = AC for matrices A, B, and C.
Is it true that B must equal C? Prove the result or find a counterexample.

Homework Equations


Properties of matrix multiplication

The Attempt at a Solution


AC = A(D + B) = AD + AB = 0 + AB = AB ? Can someone help me understand in plain english?
 
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cosmos42 said:

Homework Statement


Suppose that AB = AC for matrices A, B, and C.
Is it true that B must equal C? Prove the result or find a counterexample.

Homework Equations


Properties of matrix multiplication

The Attempt at a Solution


AC = A(D + B) = AD + AB = 0 + AB = AB ? Can someone help me understand in plain english?

If you write AB = AC as A(B-C) = 0, is it true that B-C = 0? That is, does having AD = 0 imply that D must = 0?
 
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IF A has an inverse the AB= AC gives A^{-1}AB= A^{-1}AC so IB= IC so B= C so you question becomes "does every matrix have an inverse?".

By the way, your question, as stated, is trivially false even for numbers: 0B= 0C for any B and C, it does NOT follow that B= C. To make you question at all interesting you should add "A non-zero".
 
HallsofIvy said:
IF A has an inverse the AB= AC gives A^{-1}AB= A^{-1}AC so IB= IC so B= C so you question becomes "does every matrix have an inverse?".

By the way, your question, as stated, is trivially false even for numbers: 0B= 0C for any B and C, it does NOT follow that B= C. To make you question at all interesting you should add "A non-zero".
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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