B Understanding Nuclear Bombs: The Physics Behind Their Devastation

Metals
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Now I'm familiar with how nuclear fission works to produce thermal energy and alpha/ beta/gamma radiation, but how do they work in the bomb? When is the high energy neutron fired into the uranium-235, and when does the chain reaction producing the heat begin?

Why is it that there's a huge explosion all of a sudden when the bomb impacts with a surface with high force?

If 0.1% of the uranium's mass is converted to energy, what happens to the uranium after the bomb explodes? Is it just melted and dissipated?

I understand these are not really good questions, but I'd like to better understand the practicality of the bombs. Also, are the answers the same thing for plutonium-239 bombs?
Much appreciated.
 
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Metals said:
Now I'm familiar with how nuclear fission works to produce thermal energy and alpha/ beta/gamma radiation, but how do they work in the bomb? When is the high energy neutron fired into the uranium-235, and when does the chain reaction producing the heat begin?

Why is it that there's a huge explosion all of a sudden when the bomb impacts with a surface with high force?

If 0.1% of the uranium's mass is converted to energy, what happens to the uranium after the bomb explodes? Is it just melted and dissipated?

I understand these are not really good questions, but I'd like to better understand the practicality of the bombs. Also, are the answers the same thing for plutonium-239 bombs?
Much appreciated.
Have you read the wikipedia page on this yet? https://en.wikipedia.org/wiki/Nuclear_weapon#Fission_weapons
 
Metals said:
Why is it that there's a huge explosion all of a sudden when the bomb impacts with a surface with high force?
There is not. The explosion has to be started deliberately, and with very precise timing. If the bomb just hits something, in the worst case the explosives inside detonate, but you don't get a nuclear explosion.
Metals said:
If 0.1% of the uranium's mass is converted to energy, what happens to the uranium after the bomb explodes? Is it just melted and dissipated?
The fission products (not uranium any more) get distributed in the environment.

See the Wikipedia article for the details how the explosion process works.
 
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mfb said:
There is not. The explosion has to be started deliberately, and with very precise timing. If the bomb just hits something, in the worst case the explosives inside detonate, but you don't get a nuclear explosion.

One example of this is https://en.wikipedia.org/wiki/1966_Palomares_B-52_crash
 
The US alone had so many officially recognized incidents that the Wikipedia page just lists the most noteworthy (and links to a really long list of military accidents involving nuclear weapon materials). At least according to what got made public, some nuclear weapons have never been found. A few times the chemical explosives exploded, but no accidental nuclear explosion.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

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