Understanding Phasors and Complex Numbers in Harmonic Functions

AI Thread Summary
The discussion focuses on calculating the phasors F(t) and G(t) for the functions f(t) = Acosω1t and g(t) = Acosω2t, and plotting them on an Argand diagram. Participants explore the complex representation of these functions, leading to F(t) = Ae^(iω1t) and G(t) = Ae^(iω2t). The challenge lies in determining the angle and magnitude of the resultant phasor F(t) + G(t) at t = π/(2ω1). Geometrical reasoning and the law of cosines are suggested to find the resultant's magnitude, but complications arise in calculating the argument. The conversation emphasizes the complexity of summing phasors and the need for careful analysis in harmonic functions.
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Homework Statement



What are the phasors F(t) and G(t) corresponding to the following functions:
f(t) = Acosω1t and g(t) = Acosω2t

Draw the phasors on Argand diagram as well as F(t)+G(t) at t = \pi/(2ω1)
and from the diagram get f(t)+g(t) as a cosine identity in the simplest form.


I tried plotting the F(t) + G(t),, but I couldn't get the angle nor the magnitude of it! any help will be appreciated ;)
 
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Can you describe in detail the Argand diagram you drew?
 
well, assuming that we write the functions on a complex form, we get F(t) = Ae^(iω1t) and G(t) = Ae^(iω2t). And by the way, it is given that ω1<w2 .. so, at the given t, the first argument is pi/2, the second one is not exact, but it's bigger than pi/2.. so, F(t) + G(t) is sum of two vectors drawn in the argand diagram.. but its argument is really complicated, and I'm not sure of it.
 
The sum is going to bisect the angle between the two phasors, and you can use some geometrical reasoning and the law of cosines to find the magnitude of the resultant.

Can you take it from there?
 
I got the argument to be pi*(ω2-ω1/4ω1 ... I could use the cosine rule to get the argument, however, I got a complicated result! I don't know if I'm on the right track!
 
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