Understanding Potential Energy and Force for a Constant Potential Function

AI Thread Summary
The potential energy function U = C/x leads to the force being calculated as F = -dU/dx. This results in a force that is directed toward the origin when C is positive, indicating attraction. As x increases, the potential energy decreases for a positive constant C. If C is negative, the force would still point toward the origin, but the behavior of potential energy would change, increasing as x increases. Understanding these relationships is crucial for solving problems involving conservative forces and potential energy.
yamama1
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Homework Statement


Potential energy function is given by U = C/x, where C is a positive constant.
a. Find the force as a function of x.
b. Is this force directed toward the origin or away from it?
c. Does the potential energy increase or decrease as x increases?
d. Answer b, and c if C is a negative constant.

Homework Equations


How do you relate U = C/x to force?

The Attempt at a Solution


I tried the formulas.
F = mg
U = mgy
But I am not sure how you relate both of them together
 
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welcome to pf!

hi yamama1! welcome to pf! :wink:

potential energy is (minus) the work done by a (conservative) force

in other words, PE = -∫F.dx,

and so F = … ? :smile:

(see the pf library for some details)
 


tiny-tim said:
hi yamama1! welcome to pf! :wink:

potential energy is (minus) the work done by a (conservative) force

in other words, PE = -∫F.dx,

and so F = … ? :smile:

(see the pf library for some details)


F = ma.
so PE = - ∫ma.
I don't know what that would equal to.
 
(just got up :zzz: …)
yamama1 said:
F = ma.
so PE = - ∫ma.
I don't know what that would equal to.

stick to the question … nobody's asked you for a

you're asked for F, you're given PE, and you have an equation relating PE and F …

so what is F (as a function of PE)? :smile:

(oh, and PE isn't -∫ma. it's -∫ma.dx = -∫mv(dv/dx)dx = -∫mvdv = -1/2 mv2)
 
apply F= -dU/dx
 
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