Understanding Sequence Notation and Finding Next 5 Terms: Homework Help

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Homework Statement


a_{n+2}=3a_{n+1}-2a_n[/itex]<br /> a_1=1, a_2=1<br /> Find the next 5 terms.<br /> <br /> <h2>Homework Equations</h2><br /> <br /> <br /> <br /> <h2>The Attempt at a Solution</h2><br /> I don&#039;t really understand the &quot;a sub n&quot; notation. Could someone do the next few terms so I can see how it&#039;s done?
 
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To find a3, for example, plug in n=1 into the first equation.

So, let n=1. Then,
a1+2 = a3 = 3a2 - 2a1 = 3(1) - 2(1) = 1
 
a_{1+2}=3a_{1+1} + 2a_1
a_3 = 3(1)-2(1) = 1?
 
cdotter said:

Homework Statement


a_{n+2}=3a_{n+1}-2a_n[/itex]<br /> a_1=1, a_2=1<br /> Find the next 5 terms.<br /> <br /> <h2>Homework Equations</h2><br /> <br /> <br /> <br /> <h2>The Attempt at a Solution</h2><br /> I don&#039;t really understand the &quot;a sub n&quot; notation.<br />
The terms in the sequence are {a<sub>1</sub>, a<sub>2</sub>, a<sub>3</sub>, ..., a<sub>n</sub>, a<sub>n+1</sub>, a<sub>n+2</sub>, ...}.<br /> <br /> The first formula says that to get the (n + 2)nd term in the sequence you need the preceding two terms, the (n + 1)st term and the nth term. <blockquote data-attributes="" data-quote="cdotter" data-source="post: 2668920" class="bbCodeBlock bbCodeBlock--expandable bbCodeBlock--quote js-expandWatch"> <div class="bbCodeBlock-title"> cdotter said: </div> <div class="bbCodeBlock-content"> <div class="bbCodeBlock-expandContent js-expandContent "> Could someone do the next few terms so I can see how it&#039;s done? </div> </div> </blockquote>Well, no, but maybe you can do them. You have a<sub>1</sub> = 1 and a<sub>2</sub> = 1. Use the first formula to get a<sub>3</sub>. Then when you have a<sub>3</sub>, use the formula again to find a<sub>4</sub>, and so on for as many terms as you need.
 
So any possible a_n always equals 1?
 
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cdotter said:
a_{1+2}=3a_{1+1} + 2a_1
a_3 = 3(1)-2(1) = 1?
The formula is

a_{1+2}=3a_{1+1} - 2a_1
 
cdotter said:
So any possible a_n always equals 1?
For this sequence, yes.

A simpler and nonrecursive definition would be an = 1 for n = 1, 2, 3, ...
 
Mark44 said:
For this sequence, yes.

A simpler and nonrecursive definition would be an = 1 for n = 1, 2, 3, ...

Ok, thank you. I kept thinking I was missing something because it's stupid to ask for the next 5 terms when they're all equal to 1.
 
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