Understanding SHM and Finding k in a Vertical Spring Lab

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In the vertical spring lab, the goal is to determine the spring constant k. At equilibrium, the force is represented by F = mg, where g is 9.8 m/s². When the system oscillates, the total force can be expressed as F = k(δ + x), where δ is the initial displacement and x is the additional displacement. To find k, one can rearrange the equation k = mg/δ, using the known values of mass and initial displacement. Understanding these relationships is crucial for accurately calculating the spring constant during oscillation.
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Homework Statement



This is another question related to the vertical spring lab where we try to determine k, the spring constant.

When the vertical mass-spring system is at equilibrium, then the F in F = kx is equal to F = mg, or 9.8.

What would the F be in F = kx when the system is oscillating?
In that case, the only information we know from the experiment is x (the displacement) and mass of the object.
I'm not sure how to move on from there.
 
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TN17 said:

Homework Statement



This is another question related to the vertical spring lab where we try to determine k, the spring constant.

When the vertical mass-spring system is at equilibrium, then the F in F = kx is equal to F = mg, or 9.8.

What would the F be in F = kx when the system is oscillating?
In that case, the only information we know from the experiment is x (the displacement) and mass of the object.
I'm not sure how to move on from there.

When the mass is initial hung, there is an initial displacement δ, so you have kδ=mg

then you displace the mass a distance 'x' such that the spring force acting is k(δ+x).
 
rock.freak667 said:
When the mass is initial hung, there is an initial displacement δ, so you have kδ=mg

then you displace the mass a distance 'x' such that the spring force acting is k(δ+x).

I understand the first part that you said because that is when it's still.
And the second part, do you mean that F = k(δ+x)? Is that when the system is oscillating?
 
TN17 said:
I understand the first part that you said.
And the second part, do you mean that F = k(δ+x)?

right, that F is the spring force which is just one of the forces acting when you displace the mass an additional distance x. You will still have the weight mg acting downwards.
 
rock.freak667 said:
right, that F is the spring force which is just one of the forces acting when you displace the mass an additional distance x. You will still have the weight mg acting downwards.
Okay.
But if the purpose was to find k, the spring constant, how would I do so when I only know δ and x?
That's the part I'm confused about from your equation.
 
TN17 said:
Okay.
But if the purpose was to find k, the spring constant, how would I do so when I only know δ and x?
That's the part I'm confused about from your equation.

If you need to get 'k' and you have 'δ', then you just need to use kδ=mg or k=mg/δ.
 
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