Understanding Simple Harmonic Motion: Checking Your Answers | Homework Help

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The discussion focuses on checking answers related to simple harmonic motion and wave properties. The correct answers identified include that the time for one cycle is called the period, potential energy is maximum at points A or B, and the frequency of a pendulum decreases if both length and mass are increased. Additionally, the product of frequency and wavelength gives the wave's speed, and the total mechanical energy of a system with a 2.0 kg mass and a spring constant of 50 N/m is calculated to be 25 J. The participant expresses confidence in their answers and indicates no further assistance is needed.
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Hi! Could you please check my answers? Thanks!

Homework Statement


Homework Equations


The Attempt at a Solution



1. The time for one cycle of a periodic process is called the (Points: 1)
amplitude.
wavelength.
frequency.
period. <-------


2. A mass is attached to a vertical spring and bobs up and down between points A and B. Where is the mass located when its potential energy is maximum? (Points: 1)
at either A or B < --------
midway between A and B
one-fourth of the way between A and B
none of the above.


3. What happens to a simple pendulum's frequency if both its length and mass are increased? (Points: 1)
It increases.
It decreases. <----------
It remains the same.
It could remain the same, increase, or decrease; it depends on the length to mass ratio.


4. For a wave, the frequency times the wavelength is the wave's (Points: 1)
speed. <--------
amplitude.
intensity.
power.


5. A 2.0 kg mass is attached to the end of a horizonal spring of spring constant 50 N/m and set into simple harmonic motion with an amplitude of 0.1 m. What is the total mechanical energy of this system? (Points: 1)
0.020 J
25 J <------- (5/(2x0.1)
0.25 J
1.0 J
 
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