Understanding Simple Harmonic Motion with Position and Acceleration Graphs

  • Thread starter Thread starter physks4dumies
  • Start date Start date
  • Tags Tags
    Harmonic
AI Thread Summary
The discussion focuses on sketching a position vs. time graph using an acceleration vs. time graph in the context of simple harmonic motion. It is established that the position graph is a cosine wave while the acceleration graph is a sine wave. Participants clarify that the position graph can be expressed as x = x_0 sin(ωt), indicating a relationship between the two graphs. There is confusion about whether the position graph should be a negative cosine function, which is confirmed to be partially correct but requires adjustment by a constant. Ultimately, the participants reach an understanding of how to relate the two graphs accurately.
physks4dumies
Messages
4
Reaction score
0

Homework Statement



Using the acceleration as a function of time graph, we are required to sketch the position as function of time graph


Homework Equations


I know that the position vs. time graph is a cosine wave and the aforementioned is a sine wave. I have NO idea how to start considering there are no numbers involved.


The Attempt at a Solution



I tried to plot the point of the a vs time graph corresponding to the position...only 1/4 back. In the end, i got a graph that looked EXACTLY like the first. help?
 
Physics news on Phys.org
if a=-\omega^2 x

it is possible to write x as a function of time...x=x_0 sin(\omega t)
 
I think this is meant to be in variables.
http://euclid.hamline.edu/~arundquist/latex/showequation.php?eqn_id=31336
so given the definition of the cosine graph, we know the amplitude and the period.
 
Last edited by a moderator:
well since the a vs t graph is a cosine function, wouldn't the x vs. t graph be a negative cosine function? (basically the same thing--inverted?)
 
physks4dumies said:
well since the a vs t graph is a cosine function, wouldn't the x vs. t graph be a negative cosine function? (basically the same thing--inverted?)

correct, though not entirely. the position graph will be adjusted by some constant. take a look at rockfreaks equation, what is it?
 
ooh i understand it now! Thanks eeryone
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top