Understanding Snapshot and History Graphs for Waves

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The discussion focuses on the confusion surrounding snapshot and history graphs for waves, particularly regarding the correct interpretation of a wave moving left. The original poster struggles with visualizing the movement of the wave and questions the accuracy of their drawn graph. Responses clarify that the leftmost point of the wave does not affect the value at x=0 until a specific time, confirming that the original poster's understanding aligns with the correct answer. Participants agree that the textbook "Physics for Scientists and Engineers: A Strategic Approach" by Randall D. Knight contains errors in its answer key. The consensus is that the original poster's interpretation is indeed correct, despite the textbook's inaccuracies.
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Homework Statement


asnapshot.jpg
figure is asnapshot.jpg
aasnapshot.jpg
correct & incorrect graphs is aasnapshot.jpg

Draw the history graph D(x=0m, t) at x= 0m for the wave shown in the figure.

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The Attempt at a Solution



I'm not quite understanding the concept of snapshot and history graphs. I think for this one the problem is that is is moving left. The graph that I drew is the wrong one. Here was my reasoning: In the figure, the graph is moving left, so shouldn't the leftmost point on the wave hit the point first? If at t=2 s this leftmost point is 1m away from x=0, then it takes 1 sec for it to arrive, so at t=3. I don't think I am visualizing this at all correctly. Could someone please explain to me why the graph on the bottom is correct? Thanks!
 
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Any thoughts would be greatly appreciated.
 
I am confused and this is really bothering me.
 
bcjochim07 said:

The Attempt at a Solution



I'm not quite understanding the concept of snapshot and history graphs. I think for this one the problem is that is is moving left. The graph that I drew is the wrong one. Here was my reasoning: In the figure, the graph is moving left, so shouldn't the leftmost point on the wave hit the point first?
Yes.

If at t=2 s this leftmost point is 1m away from x=0, then it takes 1 sec for it to arrive, so at t=3.
Yes, nothing happens (at x=0 m) until t = 3 sec.

I don't think I am visualizing this at all correctly. Could someone please explain to me why the graph on the bottom is correct? Thanks!

It's not correct. At x = 0, D is 0 until t=3 sec. The graph labeled "wrong" looks like the right one to me.
 
Yeah, see I'm having problems because there are a couple problems like this in my textbook where my drawings are completely off from what the back of the book has, so I was worried that I was not understanding this at all.
 
Wow. What's the name of this book, and the authors? Looks like you understand it better than they do!
 
My answer is the same as the original poster's..please, what are we doing wrong?!??!
 
Welcome to Physics Forums :smile:

You and the OP did it right, the book has it wrong.

What is the name of this book and its author?
 
The book's called Physics for Scientists and Engineers: A Strategic Approach (2nd ed.), Vol 3, and the author is Randall D. Knight. I also got the same answer as the OP. So the book is wrong and the OP is right?
 
  • #10
Welcome to PF :smile:

Klorey said:
The book's called Physics for Scientists and Engineers: A Strategic Approach (2nd ed.), Vol 3, and the author is Randall D. Knight. I also got the same answer as the OP. So the book is wrong and the OP is right?
You are correct.

And thank you for answering my question :biggrin:
 
  • #11
No problem :smile: Thanks for the help (and the fast reply)!
 
  • #12
I have the 6th edition of this book and the answer in the answer key is still wrong...
 

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