icystrike
- 444
- 1
2008
Summation (-1)^{i} \frac{i^2+i+1}{i!}
i=1
I guess I am suppose to apply the summation rule
and i got (-1)^{i} \frac{n(n+1)(n+2)+3n}{3i!}
Summation (-1)^{i} \frac{i^2+i+1}{i!}
i=1
I guess I am suppose to apply the summation rule
and i got (-1)^{i} \frac{n(n+1)(n+2)+3n}{3i!}