Understanding the Impact of an Electrostatic Chopper on Beam Characteristics

AI Thread Summary
The discussion focuses on the effects of an electrostatic chopper on the characteristics of a negative ion beam of He- ions. The main issue revolves around calculating the new current profile after the beam is pulsed, with the user attempting to apply a normal distribution to model the output. They express confusion regarding the peak current, which appears to decrease significantly after applying the chopper's effects. The relationship between the pulse width and the standard deviation is also highlighted, with the user seeking clarification on the transformation from a DC beam to a Gaussian pulse. Understanding these changes is crucial for accurately predicting beam behavior post-chopper.
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Homework Statement



Problematic Part of the problem:

Consider a negative ion beam of He- ions. The given beam characteristics are the beam energy (E) and the beam current (I).

An electrostatic chopper is placed on the beam line, which pulses the DC beam with a pulse width of say t_1 nanoseconds.

What are the new beam characterisitcs?

Homework Equations


Normal Distribution:
<br /> f(x)= \frac{1}{\sqrt{2 \pi \sigma^2}} e^{-\frac{t^2}{2\sigma^2}}<br />

The Attempt at a Solution



I would have said the new current profile would be, for an incident DC beam of beam current I0

I(t)=I_0\frac{1}{\sqrt{2 \pi \sigma^2}} e^{-\frac{t^2}{2\sigma^2}}

if the beam emerges from the chopper at t=0. Also, since the FWHM of the beam is given to be t_1 the standard deviation would be

\sigma=\frac{t_1}{2.354}

(from http://en.wikipedia.org/wiki/Full_width_at_half_maximum)

This seems pretty straightforward, however, this appears to be wrong because according to this, the peak current has changed, and become .046 times its initial value

I(0)=I_0 f(0) where f(x) is the normal distribution...can anyone tell me what I am doing wrong.
 
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anyone?

you can just tell me how a dc beam is chopped to a gaussian pulse...
 
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