Understanding the Radial Field Generated by an Infinite Line of Charge

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An infinite line of charge creates a radial electric field due to its symmetrical distribution, resulting in field lines that are perpendicular to the line. This symmetry ensures that any lateral components of the electric field cancel out, leaving only a radial component. The linear charge density of 8.00×10−12 C/m influences the strength of the field at a distance of 14.0 cm from the line. As the proton approaches the line at 1500 m/s, it experiences this radial electric field, which is essential for understanding its motion. The equipotential surfaces around the line are concentric cylinders, reinforcing the radial nature of the electric field.
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"Stopping the Proton"

Homework Statement



An infinitely long line of charge has a linear charge density of 8.00×10−12 C/m. A proton is at distance 14.0 cm from the line and is moving directly toward the line with speed 1500 m/s.

I just want a better understanding of this statement:

"An infinite line of charge will generate a field with only a radial component."

Why, again? I can post more parts of the problem if that's too confusing.
 
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Because the line charge is infinite, the field lines will all be perpendicular to the wire - radially outward for plus charge - if for no other reason than that any calculation of the field will find as much charge to one side as to the other and any component of the field that might be calculated for charge on one side is canceled out by the field component from an equal charge an equal distance to the other. The equipotential surfaces will then be concentric cylinders.
 
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