Understanding the Relationship between Heat Capacity and Internal Energy

AI Thread Summary
The discussion focuses on deriving the relationship between heat capacity (Cv) and internal energy (E) in a thermodynamic context. Magnus seeks assistance in expressing Cv as a function of temperature and internal energy, specifically using the provided equations. He expresses confusion regarding the differentiation process and how to connect the partition function to internal energy. Another participant suggests that the problem may be more complex than initially thought and recommends starting a new thread for broader input. The conversation highlights the challenges in applying calculus to thermodynamic equations.
mhellstrom
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Hi all,

I have to show that the heat capacity can be expressed as

Cv = Nk(1+1/45(Om/T)^2 + ...)

where the internal energy is given as

E = NkT*(1-(Om/(3T)-1/45(Om/T)^2)

Normally I would just differentiate but if I do this I get something completely different - how to proceed any hints appreciated thanks in advance

Best regards

Magnus
 
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Hi Magnus! :smile:
mhellstrom said:
I have to show that the heat capacity can be expressed as

Cv = Nk(1+1/45(Om/T)^2 + ...)

where the internal energy is given as

E = NkT*(1-(Om/(3T)-1/45(Om/T)^2)

Normally I would just differentiate*…

erm … NkT*(1 - Om/(3T) - 1/45(Om/T)^2) = Nk(T - Om/3 - 1/45(Om/T)) :redface:
 
yes of course... Thanks for the help. The partition function is also given in the exercise

<br /> q_{rot} = \frac{T}{\omega}*(1+\frac{1}{3}(\frac{\omega}{T}+\frac{1}{15}(\frac{\omega}{T})^2+...)<br />

I presume the internal energy is given as

E = -N(dLn Zrot / d beta)

I would really like to know how to get from the partition function to the internal energy.
The problem for me is how manage the differentiation of the serie. Any help or advise appreciated. Thanks in advance.

Best

Magnus
 
durrr … honestly no idea what that's all about …

i thought this was a straightforward calculus problem! :redface:

i think you'd better start a new thread, so as to get someone else to answer :smile:
 
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