Underwater Pressure sunken ocean liner

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Homework Help Overview

The discussion revolves around calculating the gauge pressure and depth of a sunken ocean liner based on the absolute pressure experienced by a robot observation submarine. The problem involves concepts from fluid mechanics and pressure calculations in a marine environment.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to clarify the relationship between absolute pressure and gauge pressure, questioning whether the atmospheric pressure should be considered differently underwater. They also explore the conversion of pressure from atmospheres to depth using relevant equations.

Discussion Status

Participants are engaging in a back-and-forth regarding the calculations, with some confirming the original poster's understanding of gauge pressure and the conversion process. There is a mix of affirmation and inquiry, indicating an active exploration of the concepts involved.

Contextual Notes

Participants are navigating the nuances of pressure calculations in a submerged environment, with specific attention to the definitions of absolute and gauge pressure. The discussion reflects a need to ensure clarity on the atmospheric pressure component in the context of underwater conditions.

velvetymoogle
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Homework Statement


While exploring a sunken ocean liner, the principal research found the absolute pressure on the robot observation submarine at the level of the ship to be 413 atmospheres. The density of the surrounding saltwater was 1025kg/m^3. Calculate the gauge pressure on the sunken ocean liner. Calcuate the depth of the sunken ocean liner.


Homework Equations


Pabsolute = Pgauge + Patmosphere
P=Dgh


The Attempt at a Solution


For the gauge pressure, I know that atmospheric pressure is usually 1, but because we are underwater, isn't it a lot higher or is it the force that we feel that's high?
Is it just 413 - 1 = Pgauge?

Also for depth, I know you have to conver 412 atmospheres. Do you multiply it by 1.013x10^5 because that's the conversion factor with meters in it and then just divide by (1025 x -10) to get 4071.8m below the surface of the water?
 
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Indeed; a good idea is to convert things from atmospheres into N / m^2.

Though, you can combine these two equations =).

Gauge pressure excludes atmospheric pressure by the way.
 
No, I know that. That's why I subtracted one. My work is right though, yes?
 
velvetymoogle said:
No, I know that. That's why I subtracted one. My work is right though, yes?

All your work is fine. :smile:
 

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