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Uniform Circular Motion and Centripetal Force

  1. Mar 22, 2014 #1
    Hey guys, first post here! Hoping to get a little help.
    1. The problem statement, all variables and given/known data

    You are a traffic safety engineer in charge of determining safe speeds for roads. A particular banked curve has a radius of 11.0 meters and is banked at an angle of 8.00°. The coefficient of static friction between common tires and this road is 0.870. What is the maximum speed that a car can drive this curve? Use both the bank of the curve and the friction on the tires in determining your answer.


    2. Relevant equations
    f=μn
    Fc=mv^2/r


    3. The attempt at a solution

    So what I did was split the force of gravity, mgcos8 in the direction perpendicular to the ramp and mgsin8 parallel. Also, the force of friction towards the center of rotation and set all forces towards the center of rotation to mv^2/r.

    Essentially, I had mgsin8 + (μ X mg X cos8)=mv^2/r.

    Common factor of m cancels and I solve for V as everything else is given. I receive an answer of 10.4 m/s. The correct answer is apparently 11.1 m/s, so close, but not close enough for a rounding issue I believe. My only other guess is that somehow I've split the vector wrong. Any help's much appreciated, thanks very much in advance.
     
  2. jcsd
  3. Mar 22, 2014 #2

    Simon Bridge

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    Welcome to PF;
    Notice that gravity acts straight down - so there is no component of the gravity force acting directly towards the center of the turn.

    Did you draw a free-body diagram?
    You need the vector sum of the forces to point horizontally towards the center - the forces are gravity, friction and the normal force from the road and they all act in different directions.
     
  4. Mar 23, 2014 #3
    Hi Simon, thanks for the response.

    Now I see it a little clearer. I did draw a free body diagram but it was incorrect. I was treating the parallel surface of the bank as straight horizontal. I'm still getting an incorrect answer however.

    As I have it, I have the sum of the horizontal forces as the normal force in the x direction (Fnsin8). I am confused as to where friction fits into all of this. If I'm correct, doesn't friction always oppose the direction of motion? In other words, would the ∑Fx= Fnx - friction in the x direction?
     
  5. Mar 23, 2014 #4

    Simon Bridge

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    Nope - a car accelerating forward in a straight line has a net friction force acting on it pointing in the same direction as the acceleration.

    In this case, this is static friction. Static friction acts one stationary objects too - more accurately: between surfaces that are instantaneously stationary wrt each other.

    It opposes the direction the surfaces would move if there were no friction.

    Consider:
    http://t0.gstatic.com/images?q=tbn:ANd9GcSfjwcftYv3-4OgKxziSLn1cHg850F5nLClXo9lngoNk7IXNoqNvQ
     
    Last edited: Mar 23, 2014
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