Uniform Circular Motion of a tire

AI Thread Summary
A tire with a diameter of 40 cm exhibits uniform circular motion at a frequency of 28 Hz. The velocity calculation involves the formula V = 2πrf, where the radius must be converted to kilometers. The calculated velocity of 126.669 km/hr is questioned as potentially incorrect. Participants suggest the possibility of a miscalculation or typo in the source material. Clarification on the calculation process is sought to resolve the discrepancy.
Muneerah
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Homework Statement



A point on the outer rim of a tire on a moving
vehicle exhibits uniform circular motion with
a frequency of 28 Hz. The diameter of the tire
is 40 cm.
How fast is the car moving?
Answer in units of km/hr.

Homework Equations



V=2 pi r f

The Attempt at a Solution



The first thing I did was finding the frequency in terms of hrs, and I got 100800 revelotions per hr. Then I found converted the radius to km so I got .0002 km. Then I found the velocity which is, 2 pi r f = 126.669 km/hr. My answer is wrong, I don't know what it is that I did wrong so if you can please help. Thank you
 
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Muneerah said:

Homework Statement



A point on the outer rim of a tire on a moving
vehicle exhibits uniform circular motion with
a frequency of 28 Hz. The diameter of the tire
is 40 cm.
How fast is the car moving?
Answer in units of km/hr.

Homework Equations



V=2 pi r f

The Attempt at a Solution



The first thing I did was finding the frequency in terms of hrs, and I got 100800 revelotions per hr. Then I found converted the radius to km so I got .0002 km. Then I found the velocity which is, 2 pi r f = 126.669 km/hr. My answer is wrong, I don't know what it is that I did wrong so if you can please help. Thank you

I'm getting the same answer. If I had to guess, your book/teacher probably miscalculated or had a typo.
 
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