Uniform rod pivoting and block/mass energy problem

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SUMMARY

The discussion centers on the dynamics of a uniform rod of mass m and length l pivoting at a point on the ground, which initiates motion in a block of mass M resting on a horizontal surface. The rod loses contact with the block at an angle θ = 30° to the horizontal. The correct ratio of M to m is determined to be 4/3, although there was initial confusion regarding the sign of angular acceleration (α), which should be considered positive as the angle decreases at an increasing rate.

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Alcatrez
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A uniform rod of mass m and length l is pivoted at a point on the ground. The rod is initially in vertical position and touching a block of mass M which is at rest on a horizontal surface. The rod is given a push of negligible force and it starts rotating about that point. This causes the block to move forward. The rod loses contact with the block at θ = 30° with horizontal. All surfaces are smooth.
Find M/m

I have conserved the energy, found a relation of

w² = -(alpha)(tantheta)

by considering x=Lcostheta and double differentiating to get a.

I am getting a correct ans of 4/3 but i had considered alpha (ang acc) to be negative which isn't correct, right?

What's wrong with this?
 
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Alcatrez said:
had considered alpha (ang acc) to be negative which isn't correct, right?
Assuming you are referring to the angle to the horizontal, that angle will decrease at an increasing rate, so both its first and second derivatives will be negative.
Have I understood your question?
 
haruspex said:
Assuming you are referring to the angle to the horizontal, that angle will decrease at an increasing rate, so both its first and second derivatives will be negative.
Have I understood your question?
Yes. That's exactly what i meant.
 

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