Why is it that the unilateral lateral Laplace transform is used when given initial conditions that are non-zero. Is there a reason that explains why it would be wrong to use the bilateral Laplace transform instead?(adsbygoogle = window.adsbygoogle || []).push({});

I know bilateral does not have any input of initial conditions but that does not explain why as it should still give a valid result. Is there some conditions that conflict with the bilateral transform being used when there is no initial rest?

Thanks

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# Unilateral and Bilateral Laplace Transform in Solving Differential Equations

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