mathsss2
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Let n be a nonzero integer. An abelian group A is called n-divisible if for every x \in A, there exists y \in A such that x=ny. An abelian group A is called n-torsionfree if nx=0 for some x \in A implies x=0. An abelian group A is called uniquely n-divisible if for any x \in A, there exists exactly one y \in A such that x=ny.
Let \mu_n : A \rightarrow A be the map \mu_n(a)=na
(a) Prove that A is n-torsionfree iff \mu_n is injective and that A is n-divisible iff \mu_n is surjective.
(b) Now suppose 0 \rightarrow A \overset{f}{\rightarrow} B \overset{g}{\rightarrow} C \rightarrow 0 is an exact sequence of abelian groups. It is easy to check that the following diagram commutes: [see attachment]
Suppose that B is uniquely n-divisible. Prove that C is n-torsionfree if and only if A is n-divisible.
Let \mu_n : A \rightarrow A be the map \mu_n(a)=na
(a) Prove that A is n-torsionfree iff \mu_n is injective and that A is n-divisible iff \mu_n is surjective.
(b) Now suppose 0 \rightarrow A \overset{f}{\rightarrow} B \overset{g}{\rightarrow} C \rightarrow 0 is an exact sequence of abelian groups. It is easy to check that the following diagram commutes: [see attachment]
Suppose that B is uniquely n-divisible. Prove that C is n-torsionfree if and only if A is n-divisible.