Uniqueness with Laplace's Equation and Robin Boundary Condn

JonoPUH
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Homework Statement


Suppose that T(x, y) satisfies Laplace’s equation in a bounded region
D and that
∂T/∂n+ λT = σ(x, y) on ∂D,
where ∂D is the boundary of D, ∂T/∂n is the outward normal deriva-
tive of T, σ is a given function, and λ is a constant. Prove that there
is at most one solution to the problem if λ > 0, and that if λ = 0
the solution is not unique, but any two solutions differ by an additive
constant.


Homework Equations


Txx+Tyy=0


The Attempt at a Solution


I have managed to show the additive inverse part for λ=0, but I'm having trouble with the λ>0 part.

I used W=S-T, where S also satisfies the above conditions, so therefore W is also a solution of Laplace's, with
∂W/∂n+λW=0.
However, I don't know where to go from there.
Do I use the identity I used in the previous part, which gives me ∫∫RWx2+Wy2dxdy=∫∂RW(∂W/∂n)ds ?
Cheers
 
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I'm still really stuck on this. Is there any more information people require to help me?
Thanks.
 
The identity you proved in the previous part is exactly what you need. If you substitute -lambda*W for dW/dn in the right integral, compare the signs of each side of the equality
 
Thanks for the tip, but could you possibly explain what you mean by the sign of each side? Is it simply that one side is positive, and the other is negative? In which case, I'm not sure how to proceed. Sorry.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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