Unit step response of RC high pass filter

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SUMMARY

The unit step response of a high-pass RC filter can be calculated using the transfer function approach, represented as Y(s)/X(s) = RCs/(1+sRC). The input X(s) is defined as 1/s, leading to the output Y(s) = RC/(1+sRC). The correct inverse Laplace transform yields y(t) = Dirac(t) - (exp(-t/RC)/RC), which includes a DC term, contrary to the initial solution that only presented y(t) = exp(-t/RC).

PREREQUISITES
  • Understanding of transfer functions in control systems
  • Familiarity with Laplace transforms
  • Knowledge of RC circuit behavior
  • Basic concepts of differential equations
NEXT STEPS
  • Study the properties of Laplace transforms in signal processing
  • Learn about the derivation of the unit step response for different filter types
  • Explore the implications of DC terms in non-homogeneous differential equations
  • Investigate the behavior of high-pass filters in various circuit configurations
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Electrical engineers, control system designers, and students studying signal processing and filter design will benefit from this discussion.

erece
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what is the unit step response of a high pass RC filter ?
I want to calculate using transfer function approach.
My solution :
Y(s)/X(s) = RCs/(1+sRC)

X(s)=1/s
Y(s)=RC/(1+sRC)
taking inverse laplace transform we should get
y(t)=exp(-t/RC)


But if we consider Y(s)=RC/(1+sRC)
RCsY(s) + Y(s) = RC
then this is a non homogeneous equation
so the solution should contain a dc term also which is a complementary function.
but the previous solution i have written above does not contain the dc term.
Please clarify this...
 
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y(t)=exp(-t/RC)
 
erece,

Please clarify this...

The inverse Laplace of RCs/(1+sRC) is Dirac(t)-exp(-t/RC)/RC, not what you posted.

Ratch
 

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