Unit vectors please check my answer

jhosamelly
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Homework Statement


if \vec{e_{1}} = 5\hat{i} - 3\hat{j} + 2\hat{k} what is the unit vector \hat{e_{1}}


Homework Equations





The Attempt at a Solution


here is my answer,, please confirm if I'm correct.

|\hat{e_{1}}| = \sqrt{\vec{e_{1}} . \vec{e_{1}}}
|\hat{e_{1}}| = \sqrt{(5\hat{i} - 3\hat{j} + 2\hat{k}) . (5\hat{i} - 3\hat{j} + 2\hat{k})}
|\hat{e_{1}}| = \sqrt{(5\hat{i}) . (5\hat{i}) + (-3\hat{j}) . (-3\hat{j}) + (2\hat{k}) . (2\hat{k})}
|\hat{e_{1}}| = \sqrt{(25+9+4)}
|\hat{e_{1}}| = \sqrt{38}


\hat{e_{1}} = \frac{5\hat{i} - 3\hat{j} + 2\hat{k}}{\sqrt{38}}

am i correct? Please check
 
Last edited:
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jhosamelly said:

Homework Statement


if \vec{e_{1}} = 5\hat{i} - 3\hat{j} + 2\hat{k}

Homework Equations



The Attempt at a Solution

That's not a unit vector.

Please state the problem you're trying to solve.
 
SammyS said:
That's not a unit vector.

Please state the problem you're trying to solve.

sorry i wasn't finished editing yet earlier.. please check my solution now. Thanks :))
 
Last edited:
jhosamelly said:

The Attempt at a Solution


here is my answer,, please confirm if I'm correct.

|\hat{e_{1}}| = \sqrt{\vec{e_{1}} . \vec{e_{1}}}
|\hat{e_{1}}| = \sqrt{(5\hat{i} - 3\hat{j} + 2\hat{k}) . (5\hat{i} - 3\hat{j} + 2\hat{k})}
|\hat{e_{1}}| = \sqrt{(5\hat{i}) . (5\hat{i}) + (-3\hat{j}) . (-3\hat{j}) + (2\hat{k}) . (2\hat{k})}
|\hat{e_{1}}| = \sqrt{(25+9+4)}
|\hat{e_{1}}| = \sqrt{38}


\hat{e_{1}} = \frac{5\hat{i} - 3\hat{j} + 2\hat{k}}{\sqrt{38}}

am i correct? Please check
Yes. That is correct .
 
Thanks.. Can you please check my other question.. I really appreciate it! Thanks again.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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