Unraveling a Challenging Integral: Solving for x-arctan(x)+c

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Homework Help Overview

The discussion revolves around evaluating the integral of the function x^2/(1+x^2), with the original poster expressing difficulty in deriving the solution, which they believe to be x-arctan(x)+c.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss various approaches to the integral, including substitution methods and trigonometric identities. Some suggest using trigonometric substitution due to the presence of 1+x^2, while others explore rewriting the function to simplify the integral.

Discussion Status

The conversation is ongoing, with participants providing insights and alternative methods for approaching the integral. There is a recognition of different strategies being explored, but no consensus has been reached on a definitive solution.

Contextual Notes

Participants note the challenge of the integral and the original poster's attempts at substitution, indicating a potential gap in understanding or application of techniques. The discussion reflects a learning environment where assumptions and methods are being questioned and explored.

sckeen1988
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1. The Problem comes down to what I think is a fairly simple integral, I just can't figure it out.

int(x^2/(1+x^2)

I know this is x-arctan(x)+c, but cannot figure out how.

I tried subbing in u for x^2, this didn't really help me with a direction to take though.
 
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if you ever see a [itex]1+x^2[/itex] you should imediately think to yourself TRIG SUBSTITUTION!

What relation do you know between [itex]sin^2[/itex] and [itex]cos^2[/itex]?

I'd start there
 
sckeen1988 said:
1. The Problem comes down to what I think is a fairly simple integral, I just can't figure it out.

int(x^2/(1+x^2)

I know this is x-arctan(x)+c, but cannot figure out how.

I tried subbing in u for x^2, this didn't really help me with a direction to take though.


First, write f(x) = x^2/(1+x^2) as f(x) = (x^2 + 1 - 1)/(1+x^2) = 1 - 1/(1+x^2), so
int(f(x)) = x - int(1/(1 + x^2)) The expression 1 + x^2 cries out for the substitution x = tan(t).

RGV
 
Ray Vickson said:
First, write f(x) = x^2/(1+x^2) as f(x) = (x^2 + 1 - 1)/(1+x^2) = 1 - 1/(1+x^2), so
int(f(x)) = x - int(1/(1 + x^2)) The expression 1 + x^2 cries out for the substitution x = tan(t).

RGV

ANGER! I knew I was forgetting something really easy, like adding and subtracting one. Thanks for the help
 

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