Unraveling the Meaning of l' = l + $\alpha$a

  • Thread starter Thread starter Warr
  • Start date Start date
AI Thread Summary
The equation l' = l + αa indicates that α is a dimensionless coefficient close to 1, suggesting it can take values like 2 or 3 but not extremes like 0 or 12352. When calculating l', if l and a are known, α can be approximated based on the context of the problem, typically around 1. This means l' will be slightly adjusted from l by a factor of a scaled by α. Understanding α's range helps in making accurate predictions in calculations involving this equation. The discussion clarifies the significance of "order of unity" in practical applications.
Warr
Messages
119
Reaction score
0
While reading a physics text, I came across an equation
l' = l + \alpha\,a, where \alpha is the order of unity. What exactly does this phrase mean (ie if I knew l and a, what would \alpha be?)
thanks
 
Last edited:
Physics news on Phys.org
Warr said:
While reading a physics text, I came across an equation
l' = l + \alpha\,a, where \alpha is the order of unity. What exactly does this phrase mean (ie if I knew l and a, what would \alpha be?)
thanks

Guess what was written was " is of order unity", no ?

It means that \alpha is a number that is not very far from 1, say 2 or 3 or so. Not 12352.0 and not 0.00002345.
 
Yes, that is exactly what was written.
so if I am doing a calculation based on this statement, what could I give the value of l' to be assuming I knew the precise values of l and a?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

Similar threads

Back
Top