Use an integrating factor to solve

Calu
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Homework Statement



Use an integrating factor to determine the general solutions of the following differential
equation:

dx/dt - 2/t = 2t3 + (4t2)(e4t)


Homework Equations



R(x) = e∫P(x).dx

The Attempt at a Solution



Usually the equation is in the form dx/dt + P(x)t = Q(x) but here I'm not sure what to do to find P(x) here as I have 1/t, t3 and t2.

I'm also not sure how to go about finding a solution either. I know that once I have found the integrating factor, I have to multiply the original equation by R(x). After that I'm not sure what to do.
 
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Well, it looks like this equation is actually separable. Just move the -2/t over, and the right side will be entirely a function of t.
 
jackarms said:
Well, it looks like this equation is actually separable. Just move the -2/t over, and the right side will be entirely a function of t.

I realized that whilst I was doing it, but the question specifically asks me to use an integrating factor. thanks for the reply though.
 
Calu said:

Homework Statement



Use an integrating factor to determine the general solutions of the following differential
equation:

dx/dt - 2/t = 2t3 + (4t2)(e4t)


Homework Equations



R(x) = e∫P(x).dx

The Attempt at a Solution



Usually the equation is in the form dx/dt + P(x)t = Q(x) but here I'm not sure what to do to find P(x) here as I have 1/t, t3 and t2.

I'm also not sure how to go about finding a solution either. I know that once I have found the integrating factor, I have to multiply the original equation by R(x). After that I'm not sure what to do.

Here, your independent variable is ##t##. So your integrating factor is ##R=e^{\int\frac 2 t~dt}##. Evaluate that and multiply through by it.
 
LCKurtz said:
Here, your independent variable is ##t##. So your integrating factor is ##R=e^{\int\frac 2 t~dt}##. Evaluate that and multiply through by it.

Oh, I see. Thanks, I was being a bit stupid there.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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