Use of the Stefan-Bolzman Law - what is the power (H)?

[GeeS]

Hi,
I want to use the stefan-boltzmann law to find the emissivity of a metal.
H = AeσT^4 - Ts^4

I have recorded area (0.064m^2), final temperature (335.23K) and ambient temperature (307.27K). The original temperature of the metal 62.23˚C, and the final temperature after 8 minutes was 32.33˚C. However when it was left to cool, it wasn't put in total darkness, so there was still some light energy coming in.

My main question is with the power (H). when finding this, is it just the power found from q = mc∆t over time, or do you add the power of the light being absorbed, and hence emitted? eg, if 42W/m^2 were being absorbed from the light, and Q found by mc∆t is 4.3W, is the power use for stefan-boltzman law 42 or 46.3?

Thanks :)

 

[LightHero]

The power used for the Stefan-Boltzmann law should be the power that is emitted from the metal, not the power that is absorbed from the light. This means that the power used in the Stefan-Boltzmann law would be 4.3W.