Use power-reducing formulas to rewrite

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The discussion focuses on rewriting the expression 152sin^2 x cos^2 x using power-reducing formulas. The participant initially attempts the calculation but arrives at an incorrect result of 30 - 30 + 30cos4x/2 instead of the expected 19 - 19cos4x. Another user suggests starting with the identity sin2xcos2x = (sinxcosx)^2 for simplification. The conversation highlights the importance of correctly applying the power-reducing formulas and performing accurate calculations. Ultimately, the participant acknowledges their mistake and expresses gratitude for the guidance.
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Homework Statement


Use power-reducing formulas to rewrite 152sin^2 x cos^2 x

Homework Equations


sin^2θ= 1-cos2θ/ 2 and cos^2θ= 1+cos2θ/2


The Attempt at a Solution


152(1-cos2x/2)(1+cos2x/2), 152/4 (1^2 - cos^2 2x), 30(1-(1+cos4x/2), and I got 30-30+30cos4x/2 as the answer but the answer is supposed to be 19-19 cos4x. I have no idea how that can be?
 
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Hi Alison! Welcome to PF! :smile:

(try using the X2 button just above the Reply box :wink:)
AlisonWagner said:
152/4 (1^2 - cos^2 2x), 30(1-(1+cos4x/2)

Nooo :redface:

(but anyway wouldn't it be simpler to start with sin2xcos2x = (sinxcosx)2 ? :wink:)
 
AlisonWagner said:

Homework Statement


Use power-reducing formulas to rewrite 152sin^2 x cos^2 x

Homework Equations


sin^2θ= 1-cos2θ/ 2 and cos^2θ= 1+cos2θ/2


The Attempt at a Solution


152(1-cos2x/2)(1+cos2x/2), 152/4 (1^2 - cos^2 2x), 30(1-(1+cos4x/2), and I got 30-30+30cos4x/2 as the answer but the answer is supposed to be 19-19 cos4x. I have no idea how that can be?

##\frac{152} 4 = 38##.
 


and then what would I do after that? Because I know we are supposed to use the power reducing formulas to solve it
 
Ooh well I guess doing the right math would help me get that...haha thanks for pointing that out! Now I know my mistake!
 
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