Using symbols to rewrite the problem and then solve it.

  • Thread starter Thread starter rcmango
  • Start date Start date
  • Tags Tags
    Symbols
AI Thread Summary
The problem involves using symbols to express "four squared divided by two to the fourth power," which is written as 4^2 / 2^4. The evaluation of this expression results in an answer of 1. A clarification is provided that if the phrasing had included a comma, changing it to "four squared divided by 2, to the fourth power," the expression would be (4^2/2)^4, yielding a result of 4096. This highlights the importance of punctuation in mathematical expressions. Understanding these nuances is crucial for accurate problem-solving.
rcmango
Messages
232
Reaction score
0

Homework Statement



use symbols to write and evaluate this problem

four squared divided by two to the fourth power

Homework Equations





The Attempt at a Solution



4^2 / 2^4

the answer I get is 1
 
Physics news on Phys.org
rcmango said:

Homework Statement



use symbols to write and evaluate this problem

four squared divided by two to the fourth power

Homework Equations





The Attempt at a Solution



4^2 / 2^4

the answer I get is 1

Looks good.
 
By the way, if the statement had been "four squared divided by 2, to the fourth power" (note the comma!) it would be (4^2/2)^4, which is 4096.
 
Thankyou.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top