Using the formula 1/f = 1/object distance + 1/image distance, in the

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SUMMARY

The discussion focuses on the optical implications of using the lens formula 1/f = 1/object distance + 1/image distance with two plano-convex lenses glued together. When the image distance (d_i) from the first lens is negative, it indicates the formation of a virtual image. This occurs because the cemented doublet behaves as a single lens with negative power, resulting in the virtual image being located in front of the second lens.

PREREQUISITES
  • Understanding of the lens formula 1/f = 1/object distance + 1/image distance
  • Knowledge of plano-convex lens characteristics
  • Familiarity with the concept of virtual images in optics
  • Basic principles of lens power and its effects on image formation
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  • Study the properties of plano-convex lenses and their applications in optical systems
  • Explore the concept of lens power and how it affects image formation
  • Learn about virtual images and their significance in optical design
  • Investigate the behavior of cemented doublets in various optical configurations
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Optics students, optical engineers, and anyone interested in understanding lens behavior and image formation in complex lens systems.

avocadogirl
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Using the formula 1/f = 1/object distance + 1/image distance,
in the instance where you have two plano-convex lenses glued together on their flat sides, what does it mean if your image distance from the first lens is negative? is the image in front of the second lens or behind the second lens?

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since we can consider the cemented doublet as a single lens, having d_i <0 means it is a virtual image (the doublet has negative power).
 

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